遍历列表一部分的pythonic方法 [英] pythonic way to iterate over part of a list

问题描述

我想遍历列表中除前几个元素外的所有内容，例如:

I want to iterate over everything in a list except the first few elements, e.g.:

for line in lines[2:]:
    foo(line)

这很简洁，但是复制了整个列表，这是不必要的.我可以做到:

This is concise, but copies the whole list, which is unnecessary. I could do:

del lines[0:2]
for line in lines:
    foo(line)

但这会修改​​列表，但并不总是很好.

But this modifies the list, which isn't always good.

我可以这样做:

for i in xrange(2, len(lines)):
    line = lines[i]
    foo(line)

但是，那只是毛病.

更好的可能是这样:

for i,line in enumerate(lines):
    if i < 2: continue
    foo(line)

但这并不像第一个例子那么明显.

But it isn't quite as obvious as the very first example.

因此:有什么方法可以像第一个示例一样显而易见，但是不会不必要地复制列表?

So: What's a way to do it that is as obvious as the first example, but doesn't copy the list unnecessarily?

推荐答案

您可以尝试 itertools.islice(iterable[, start], stop[, step]) :

You can try itertools.islice(iterable[, start], stop[, step]):

import itertools
for line in itertools.islice(list , start, stop):
     foo(line)

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