获取具有给定索引的Python列表的子列表? [英] Getting a sublist of a Python list, with the given indices?

问题描述

我有一个Python列表，例如a = [0,1,2,3,4,5,6].我也有一个索引列表，例如b = [0,2,4,5].如何在b中获得带有索引的a元素列表?

I have a Python list, say a = [0,1,2,3,4,5,6]. I also have a list of indices, say b = [0,2,4,5]. How can I get the list of elements of a with indices in b?

推荐答案

您可以使用列表理解来获取该列表:

You can use list comprehension to get that list:

c = [a[index] for index in b]
print c

这等效于:

c= []
for index in b:
    c.append(a[index])
print c

输出:

[0,2,4,5]

注意:

请记住，some_list[index]是用于访问特定索引中的list元素的符号.

Remember that some_list[index] is the notation used to access to an element of a list in a specific index.

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