如何根据子列表的长度对列表列表进行排序 [英] How to sort list of lists according to length of sublists

问题描述

我有以下列表

a = [['a', 'b', 'c'], ['d', 'e'], ['f', 'g', 'h'], ['i', 'j', 'k', 'l'], ['m', 'n'], ['o']]

我想根据其子列表的长度对列表进行排序. 结果应为:

I would like to sort the list based on the length of their sub lists. The result should be like:

a = [['o'],['d','e'],['m', 'n'],['a', 'b', 'c'],['f', 'g', 'h'], ['i','j','k','l']]

推荐答案

使用sort和sorted中可用的key参数.它指定一个参数的功能，该参数用于从每个列表元素中提取比较键

Use key parameter available in sort and sorted. It specifies a function of one argument that is used to extract a comparison key from each list element

In [6]: a = [['a', 'b', 'c'], ['d', 'e'], ['f', 'g', 'h'], ['i', 'j', 'k', 'l'], ['m', 'n'], ['o']]

In [7]: a.sort(key=len)

In [8]: print a
[['o'], ['d', 'e'], ['m', 'n'], ['a', 'b', 'c'], ['f', 'g', 'h'], ['i', 'j', 'k', 'l']]

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