元组列表中按字母求和的数字 [英] Sum numbers by letter in list of tuples

问题描述

我有一个元组列表:

[ ('A',100), ('B',50), ('A',50), ('B',20), ('C',10) ]

我正在尝试对所有具有相同字母的数字求和. IE.我想输出

I am trying to sum up all numbers that have the same letter. I.e. I want to output

[('A', 150), ('B', 70), ('C',10)] 

我尝试使用set获得唯一值，但是当我尝试将第一个元素与set比较时，我得到

I have tried using set to get the unique values but then when I try and compare the first elements to the set I get

TypeError: unsupported operand type(s) for +: 'int' and 'str'

有什么快速解决方案可以按字母匹配数字?

Any quick solutions to match the numbers by letter?

推荐答案

这里是一个(一半?)划线:按字母分组(您需要在其之前进行排序)，然后取第二个的总和元组的条目.

Here is a one(and a half?)-liner: group by letter (for which you need to sort before), then take the sum of the second entries of your tuples.

from itertools import groupby
from operator import itemgetter

data = [('A', 100), ('B', 50), ('A', 50), ('B', 20), ('C', 10)]
res = [(k, sum(map(itemgetter(1), g)))
       for k, g in groupby(sorted(data, key=itemgetter(0)), key=itemgetter(0))]
print(res)
// => [('A', 150), ('B', 70), ('C', 10)]

以上是O(n log n)—分拣是最昂贵的操作.如果您的输入列表确实很大，那么以下O(n)方法可能会更好地为您服务:

The above is O(n log n) — sorting is the most expensive operation. If your input list is truly large, you might be better served by the following O(n) approach:

from collections import defaultdict

data = [('A', 100), ('B', 50), ('A', 50), ('B', 20), ('C', 10)]

d = defaultdict(int)
for letter, value in data:
    d[letter] += value
res = list(d.items())
print(res)
// => [('B', 70), ('C', 10), ('A', 150)]

这篇关于元组列表中按字母求和的数字的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！