python:从列表创建元组列表 [英] python: create list of tuples from lists

问题描述

我有两个列表:

x = ['1', '2', '3']
y = ['a', 'b', 'c']

，我需要从这些列表中创建一个元组列表，如下所示:

and I need to create a list of tuples from these lists, as follows:

z = [('1','a'), ('2','b'), ('3','c')]

我尝试过这样:

z = [ (a,b) for a in x for b in y ]

但导致:

[('1', '1'), ('1', '2'), ('1', '3'), ('2', '1'), ('2', '2'), ('2', '3'), ('3', '1'), ('3', '2'), ('3', '3')]

即x中每个元素与y中每个元素的元组列表...做我想做的正确方法是什么?谢谢...

i.e. a list of tuples of every element in x with every element in y... what is the right approach to do what I wanted to do? thank you...

编辑:编辑前提到的其他两个重复是我的错，错误地将其缩进了另一个for循环中...

The other two duplicates mentioned before the edit is my fault, indented it in another for-loop by mistake...

推荐答案

使用内置函数 zip() :

Use the builtin function zip():

在Python 3中:

In Python 3:

z = list(zip(x,y))

在Python 2中:

In Python 2:

z = zip(x,y)

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