如何从R中的列表中子集化 [英] How to subset from a list in R

问题描述

我的任务很简单，但是找不到一个好的解决方案.

I have a rather simple task but haven't find a good solution.

> mylist  
[[1]]
 [1]  1  2  3  4  5  6  7  8  9 10

[[2]]
 [1] "a" "b" "c" "d" "e" "f" "g" "h" "i" "j" "k" "l" "m" "n" "o" "p" "q" "r" "s" "t" "u" "v" "w" "x" "y" "z"

[[3]]
[1] 25 26 27 28 29 30 31 32

y <- c(3,5,9)    

我想从 mylist 中提取列表中每个组件的子元素3,5和9. 我已经尝试了sapply[mylist,"[[",y]，但是没有运气！，还有其他类似vapply，lapply等的东西.在此先感谢您的帮助

I would like to extract from mylist the sub-elements 3,5, and 9 of each component in the list. I have tried, sapply[mylist,"[[",y] but not luck!, and others like vapply, lapply, etc.. Thanks in advance for your help

毛里西奥·奥尔蒂斯

推荐答案

您可以使用sapply(mylist, "[", y):

mylist <- list(1:5, 6:10, 11:15)
sapply(mylist, "[", c(2,3))

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