在单独的行中打印列表列表 [英] Print list of lists in separate lines

问题描述

我有一个列表列表:

a = [[1, 3, 4], [2, 5, 7]]

我想要以下格式的输出:

I want the output in the following format:

1 3 4
2 5 7

我已经尝试通过以下方式进行尝试，但是输出的效果不理想:

I have tried it the following way , but the outputs are not in the desired way:

for i in a:
    for j in i:
        print(j, sep=' ')

输出:

1
3
4
2
5
7

在更改打印调用以改为使用end时:

While changing the print call to use end instead:

for i in a:
    for j in i:
        print(j, end = ' ')

输出:

1 3 4 2 5 7

有什么想法吗?

推荐答案

遍历原始列表中的每个子列表，并使用*在打印调用中将其解压缩:

Iterate through every sub-list in your original list and unpack it in the print call with *:

a = [[1, 3, 4], [2, 5, 7]]
for s in a:
    print(*s)

默认情况下，分隔设置为' '，因此无需显式提供分隔.打印:

The separation is by default set to ' ' so there's no need to explicitly provide it. This prints:

1 3 4
2 5 7

在您的方法中，您要对每个子列表中的每个元素进行迭代，并分别进行打印.通过使用print(*s)您可以解压缩打印调用中的列表，这实际上可以转换为:

In your approach you were iterating for every element in every sub-list and printing that individually. By using print(*s) you unpack the list inside the print call, this essentially translates to:

print(1, 3, 4)  # for s = [1, 2, 3]
print(2, 5, 7)  # for s = [2, 5, 7]

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