Python-将带有数字的字符串转换为整数列表 [英] Python - Convert string with numbers into a list of integers

问题描述

我已经在SO上阅读了有关此问题的几个问题，但是这些问题都没有为我解决-我想我做错了.

I've read several questions about this on SO, however, none of them worked out for me - I guess I'm doing something wrong.

我有一个字符串，数字用逗号和空格隔开，如下所示:

I have a string with numbers separated with commas and spaces which looks like this:

my_string = '32, 76, 82, 19, 25'

现在我想拥有的是上面字符串中数字的整数列表，因此我可以像这样从中提取单个整数:

Now what I would like to have is a list of integers of the numbers in the string above, so I can extract single integers from it like this:

print my_list[2]
>>>82

或

print my_list[4]
>>>25

提前谢谢！

推荐答案

将问题分为两部分.

1将文本拆分为包含所需数据的列表，然后过滤其他文本.

1 Split the text into a list with the data you need and filter the other.

num_list = my_string.split(',')

2将数据转换为所需的类型

2 Convert the data into what type you want it

integers = [int(x) for x in num_list]

然后您可以清理它

integs = [int(x) for x in my_string.split(',')]

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