Python，如何基于总和对列表进行排序 [英] Python, how to sort a list based on a sum

问题描述

a = [('dog', 4, 5), ('cat', 1, 3), ('house', 6, 3), ('car', 1, 1), ('boyfriend', 2, 2), ('doll', 1, 1)

如何根据两个数字之间的总和对该列表进行降序排序；如果总和相同，如何根据第一个元素对它进行排序?

How can i sort this list in a descending order based on the sum between the two numbers and, if the sum is the same, how can i sort it based on the first element?

我的清单应该是:

a = [('dog', 4, 5), ('house', 6, 3), ('boyfriend', 2, 2), ('cat', 1, 3), ('car', 1, 1), ('doll', 1, 1) 

推荐答案

使用自定义key函数返回 tuple ，其中第一项是总和，第二个是每个子元素的第一项:

Use the custom key function returning a tuple where the first item is the sum and the second is the first item of each subelement:

In [2]: sorted(a, key=lambda item: (-(item[1] + item[2]), item[0]))
Out[2]: 
[('dog', 4, 5),
 ('house', 6, 3),
 ('boyfriend', 2, 2),
 ('cat', 1, 3),
 ('car', 1, 1),
 ('doll', 1, 1)]

请注意，我们会将负和返回按和进行反向排序，并保持对二级键排序的要求不断提高.

Note that we are returning the negative sum to reverse-sort by the sum and keeping the requirement for the secondary key sort to be ascending.

这篇关于Python，如何基于总和对列表进行排序的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！