在python列表中使用startswith()函数 [英] Using startswith() function inside lists in python

问题描述

我在下面有以下字符串的列表

I had the list with following strings below

some_list = ['9196358485','9966325645','8846853128','8-4-236/2','9-6-32/45','Need to fetch some strings']

从上面的字符串中，我只希望不是以91,9,8开头的字符串，而是要以8-, 9-

From the above strings i want only strings that does n't start with 91,9,8 but want strings starting with 8-, 9-

下面是我的代码

[i for i in some_list if all(not i.startswith(x) for x in ['91','8','9'])]

结果:

['Need to fetch some strings']

在上面通过使用['91','8','9']作为条件是删除以9 and 8开头的字符串，这是正确的，但是我不希望从列表中也删除9-, 8-，实际上我的意图是以9 and 8开头的字符串应该像上面那样被忽略，以9- and 8-开头的字符串也不应该被忽略，我们是否可以在一行中编写两个条件，以采用以8-,9-开头的字符串并忽略何时以在我编写的上述代码中.

In the above by using ['91','8','9'] as the condition is deleting the strings starting with 9 and 8 which is correct, but i don't want 9-, 8- also to be removed from the list, actually my intension is if the strings starting with 9 and 8 should be ignored as above and strings starting with 9- and 8- should not be ignored , can we write two conditions in a single line with concept of taking strings starting with 8-,9- and ignoring when strings starts with 9 or 8 in the above code i had written.

任何人都可以让我知道做这件事.............

Can anyone please let me know hoe to do this.............

修改后的代码:

感谢您的支持，如果您不认为这是另一个问题，我有一些实际输出，下面的代码不起作用

Thanks for all of u r support if u don't think this is another question i had some actual output on which the below code is not working

some_list = ['Mr K V  Prasad Reddy(MD)',
 '+(91)-9849633132, 9959455935',
 '+(91)-9849633132',
 'Near NRI College,Opp Vijaya Bank,Nizam Pet Road,Nizampet,Hyderabad - 502102',
 '9196358485',
 '9966325645', 
 '8846853128',
 '8-4-236/2',
 '9-6-32/45',
 'Need to fetch some strings']

当我使用正则表达式应用bwlow代码时，得到以下输出 结果:

When i apply the bwlow code using regex i got following output result:

['Mr K V  Prasad Reddy(MD)',
 '+(91)-9849633132, 9959455935',
 '+(91)-9849633132',
 'Near NRI College,Opp Vijaya Bank,Nizam Pet Road,Nizampet,Hyderabad - 502102',
 '8-4-236/2',
 '9-6-32/45',
 'Need to fetch some strings']

实际上我不希望列表中包含所有电话号码，因此有时会以上述格式使用91有时8有时9

Actually i don't want all phone numbers from the list, so they will be in the above format sometimes starting with 91 sometimes 8 sometimes 9

我们如何从列表中删除所有这些电话号码?

How can we remove all those phone numbers from the list?

推荐答案

使用正则表达式:

>>> import re
>>> [i for i in some_list if not re.match(r"[98]\B|+\(91\)", i)]
['8-4-236/2', '9-6-32/45', 'Need to fetch some strings']

\B仅在字母数字字符串中匹配，因此它在9和1之间匹配，而在9和-之间不匹配.

\B matches only within alphanumeric strings, so it matches between 9 and 1 but not between 9 and -.

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