在Python中一次遍历2个列表 [英] Iterate through 2 lists at once in Python

查看:614
本文介绍了在Python中一次遍历2个列表的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我想与两个Python列表的成员共享/划分特定数量. list1的成员将具有双重共享,而list2的成员将具有单一共享,然后打印出结果,并分配名称和值.以下是我的示例代码:

I want to share/divide a specific amount to the members of two Python lists. The members of list1 will have double share each, while the members of list2 will have single share each, then print out the result, with name and value allocated. The following is my sample code:

reminder = float(85000)

list1 = ['Designer', 'Coder', 'Supervisor']
list2 = ['Artist', 'Attendant', 'Usher]

for i,j in list1 and list2:
    print(i, (reminder/9)*2)
    print(j, (reminder/9)*1)

当我运行上面的代码时,我得到了一个例外:

When I ran the above code I got an exception:

Traceback (most recent call last):
  File "C:\Python33\reminder.py", line 6, in <module>
    for i,j in list1 and list2:
ValueError: too many values to unpack (expected 2)

我搜索了同一主题的先前帖子,但找不到解决方案.

I searched previous posts on same topic but could't come across a solution.

请问该如何处理?

推荐答案

您应使用 zip()内置函数.

for i, j in zip(list1, list2):
    print(i, (reminder/9)*2)
    print(j, (reminder/9)*1)

这篇关于在Python中一次遍历2个列表的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆