尝试在Python中扩展列表时出现类型错误 [英] Type error when trying to extend a list in Python
问题描述
我需要了解原因:
years = range(2010,2016)
years.append(0)
是可能的,返回:
[2010,2011,2012,2013,2014,2015,0]
和
years = range(2010,2016).append(0)
或
years = [0].extend(range(2010,2016))
行不通吗?
我了解这是我收到的消息中的类型错误.但我想在此后面提供更多解释.
I understand that it is a type error from the message I got. But I'd like to have a bit more explanations behind that.
推荐答案
您正在存储list.append()
或list.extend()
方法的结果;都更改列表到位,并返回None
.他们不会不再次返回列表对象.
You are storing the result of the list.append()
or list.extend()
method; both alter the list in place and return None
. They do not return the list object again.
不存储None
结果;存储range()
结果, then 扩展或追加.或者,使用串联:
Do not store the None
result; store the range()
result, then extend or append. Alternatively, use concatenation:
years = range(2010, 2016) + [0]
years = [0] + range(2010, 2016)
请注意,我假设您使用的是Python 2(否则您的第一个示例将无法正常工作).在Python 3中,range()
不会产生列表.您必须使用list()
函数将其转换为一个:
Note that I'm assuming you are using Python 2 (your first example would not work otherwise). In Python 3 range()
doesn't produce a list; you'd have to use the list()
function to convert it to one:
years = list(range(2010, 2016)) + [0]
years = [0] + list(range(2010, 2016))
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