在列表中查找列表的最大值，并返回单独的列表值python [英] Finding max of list in lists and returning a separate list value python

问题描述

因此，我有一个包含多个并行对象列表的列表，我想在列表中找到一个索引的最大值，在这种情况下为[5].

So I have a list which contains multiple parallel object lists and I want to find the max value of one index in the list, in this case [5].

一旦有了最大值，我将如何找到它的出现位置并返回该列表的第一个元素?

Once I have the max value, how would I find where that occurs and return the first element of that list?

例如，inputlist = [[70, 'Cherry St,', 43.684371, -79.316756, 23, 9, 14, True, True], [78, 'Cow Rd', 43.683378, -79.322961, 15, 13, 2, True, False]]

For example, inputlist = [[70, 'Cherry St,', 43.684371, -79.316756, 23, 9, 14, True, True], [78, 'Cow Rd', 43.683378, -79.322961, 15, 13, 2, True, False]]

我如何让我的函数返回78，因为它包含列表列表中index [5]的最大值?

How can I get my function to return 78 as it contains the maximum value of index[5] in my list of lists?

推荐答案

使用 max() 函数，但通过一个参数来检查特定的索引:

Use the max() function, but pass through an argument to check a specific index:

max(inputList, key=lambda x: x[5])

这将返回inputList中具有最大索引5值的子列表.如果要实际访问此值，请在语句末尾添加[5].

This returns the sublist in inputList that has the greatest value at index 5. If you want to actually access this value, add [5] to the end of the statement.

由于似乎您希望列表的ID包含最多5个元素，因此在末尾添加[0]:

Since it seems that you want the ID of the list with the maximum 5th element, add [0] to the end:

max(inputList, key=lambda x: x[5])[0]

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