在Python中使用列表理解来执行类似于zip()的操作? [英] Using list comprehension in Python to do something similar to zip()?

问题描述

我是一名Python新手，我想做的一件事就是将自己的头放在列表理解上.我看到它是一个非常强大的功能，值得学习.

I'm a Python newbie and one of the things I am trying to do is wrap my head around list comprehension. I can see that it's a pretty powerful feature that's worth learning.

cities = ['Chicago', 'Detroit', 'Atlanta']
airports = ['ORD', 'DTW', 'ATL']

print zip(cities,airports)
[('Chicago', 'ORD'), ('Detroit', 'DTW'), ('Atlanta', 'ATL')]

如何使用列表推导，以便将结果作为列表中的一系列列表而不是列表中的一系列元组得到?

How do I use list comprehension so I can get the results as a series of lists within a list, rather than a series of tuples within a list?

[['Chicago', 'ORD'], ['Detroit', 'DTW'], ['Atlanta', 'ATL']]

(我意识到在这种情况下，字典可能更合适，但我只是想更好地理解列表).谢谢！

(I realize that dictionaries would probably be more appropriate in this situation, but I'm just trying to understand lists a bit better). Thanks!

推荐答案

类似以下内容:

[[c, a] for c, a in zip(cities, airports)]

或者，list构造函数可以将元组转换为列表:

Alternately, the list constructor can convert tuples to lists:

[list(x) for x in zip(cities, airports)]

或者，在这种情况下，map函数的详细程度略有降低:

Or, the map function is slightly less verbose in this case:

map(list, zip(cities, airports))

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