如何将多个列表映射到一本词典? [英] How to map multiple lists to one dictionary?

问题描述

我使用了以下代码:

dictionary = dict(zip(list1, list2))

以便在字典中映射两个列表.其中:

in order to map two lists in a dictionary. Where:

list1 = ('a','b','c')
list2 = ('1','2','3')

字典等于:

{'a': 1, 'c': 3, 'b': 2}

是否可以添加第三个列表:

Is there a way to add a third list:

list3 = ('4','5','6')

以便字典等于:

{'a': [1,4], 'c': [3,5], 'b': [2,6]}

必须添加第三个列表，以使其遵循现有映射.

This third list has to be added so that it follows the existing mapping.

这个想法是让它在for循环中迭代地完成这项工作，并为正确映射的关键字提供数十个值. 这样可能吗?

The idea is to make this work iteratively in a for loop and several dozens of values to the correctly mapped keyword. Is something like this possible?

希望我的问题很清楚.

推荐答案

dict((z[0],list(z[1:])) for z in zip(list1,list2,list3))

将起作用.或者，如果您更喜欢python2.7 +的更好的dict-comprehension语法，则

will work. Or, if you prefer the slightly nicer dict-comprehension syntax of python2.7+

{z[0]:list(z[1:]) for z in zip(list1,list2,list3)}

这可以轻松扩展到任意数量的列表:

This scales up to to an arbitrary number of lists easily:

list_of_lists = [list1,list2,list3,...]
{z[0]:list(z[1:]) for z in zip(*list_of_lists)} 

如果要转换类型以确保值列表包含所有整数:

And if you want to convert the type to make sure that the value lists contain all integers:

def to_int(iterable):
    return [int(x) for x in iterable]

{z[0]:to_int(z[1:]) for z in zip(*list_of_lists)}

当然，您可以在1行中完成此操作，但我宁愿不这样做.

Of course, you could do that in 1 line, but I'd rather not.

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