在列表中查找最受欢迎的单词 [英] Finding the most popular words in a list

问题描述

我有一个单词列表:

words = ['all', 'awesome', 'all', 'yeah', 'bye', 'all', 'yeah']

我想获取一个元组列表:

And I want to get a list of tuples:

[(3, 'all'), (2, 'yeah'), (1, 'bye'), (1, 'awesome')]

每个元组在哪里...

where each tuple is...

(number_of_occurrences, word)

该列表应按出现次数进行排序.

The list should be sorted by the number of occurrences.

到目前为止我所做的:

def popularWords(words):
    dic = {}
    for word in words:
        dic.setdefault(word, 0)
        dic[word] += 1
    wordsList = [(dic.get(w), w) for w in dic]
    wordsList.sort(reverse = True)
    return wordsList

问题是...

它是Pythonic，优雅且高效的吗? 你能做得更好吗? 预先感谢.

Is it Pythonic, elegant and efficient? Are you able to do it better? Thanks in advance.

推荐答案

您可以使用它使元组具有反向列.

It gives the tuple with reversed columns.

从注释中:collections.counter为> = 2.7,3.1.您可以将计数器食谱用于较低版本.

From the comments: collections.counter is >=2.7,3.1. You can use the counter recipe for lower versions.

这篇关于在列表中查找最受欢迎的单词的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！