如何在R中的列表中合并具有不同长度的向量? [英] how to combine vectors with different length within a list in R?

问题描述

合并列表中包含的以下向量时出现问题:

I have a problem when combining the following vectors included in the list:

x <- list(as.numeric(c(1,4)),as.numeric(c(3,19,11)))
names (x[[1]]) <- c("species.A","species.C")
names (x[[2]]) <- c("species.A","species.B","species.C")

给出以下列表:

>x
>[[1]]
>species.A species.C 
>         1         4 
>[[2]]
>species.A species.B species.C 
>        3        19        11 

使用do.call函数将它们组合: y<- do.call(cbind,x)

combining them using the do.call function: y<- do.call(cbind,x)

给予:

>y
>             [,1] [,2]
>   species.A    1    3
>   species.B    4   19
>   species.C    1   11

同时我想获得这个:

>             [,1] [,2]
>   species.A    1    3
>   species.B   NA   19
>   species.C    4   11

推荐答案

似乎您实际上是在尝试进行合并.这样，merge将起作用.您只需要告诉它合并名称，并保留所有行即可.

It looks like you're actually trying to do a merge. As such, merge will work. You just have to tell it to merge on the names, and to keep all rows.

do.call(merge, c(x, by=0, all=TRUE))   # by=0 and by="row.names" are the same

(这将创建一个数据框，而不是一个矩阵，但对于大多数目的而言，这应该不是问题.)

(This will create a data frame rather than a matrix, but for most purposes that shouldn't be an issue.)

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