如何使用列表切片从列表中获取除第一个元素以外的所有内容 [英] How to get everything from the list except the first element using list slicing

问题描述

所以我要解析一些内容，但是下面是我想做的一个例子:

list = ['A', 'B', 'C']

然后使用列表切片将除第一个索引之外的所有内容都返回给我.因此，在这种情况下:

['B', 'C']

我一直在弄乱诸如list [:-1]，list [::-1]，list [0:-1]之类的东西，但是我似乎无法找到答案. /p>

我实际正在做的是: *我有一条错误消息，开头有错误代码，例如:

['226', 'Transfer', 'Complete']

，我只想在弹出窗口小部件上显示传输完成".当然，我要转换为字符串.

感谢您提供的所有帮助，如果Python 2.7.x和Python 3.x.x的答案有所不同，请同时回答这两个版本.

谢谢，在stackoverflow上看了很多，而python教程并不能真正得到我想要的东西.感谢您的帮助！

解决方案

您可以执行[1:]. 这将在两个版本上都适用.

So I have something that I am parsing, however here is an example of what I would like to do:

list = ['A', 'B', 'C']

And using list slicing have it return to me everything but the first index. So in this case:

['B', 'C']

I have been messing with stuff like list[:-1], list[::-1], list[0:-1], etc. But I can't seem to be able to find this out.

What I am actual doing is: * I have a error message that has a error code in the beginning such as:

['226', 'Transfer', 'Complete']

and I want to just display Transfer Complete on a popup widget. Of course I am casting to a string.

Thank you for all help, and if answer differs via Python 2.7.x and Python 3.x.x Please answer for both versions.

Thanks, looked a lot around stackoverflow and python tutorials couldn't really quite get what I was looking for. Thanks for your help!

解决方案

You can just do [1:]. This will work on both versions.

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