查找两个嵌套列表之间的差异 [英] Finding the differences between two nested lists

问题描述

我有一个嵌套列表和另一个嵌套列表，它是第一个列表的子集:

I have a nested list and another nested list which is a subset of the first list:

lst = [[1, 2], [3, 4], [1, 2], [5, 6], [8, 3], [2, 7]]
sublst = [[1, 2], [8, 3]]

如何找到不在子列表中的内部列表.使用以上示例的期望输出是:

How can I find the inner lists which are not in the sublist. The desired output using the above example is:

diff = [[3, 4], [5, 6], [2, 7]]

推荐答案

使用列表理解:

In [42]: lst = [[1, 2], [3, 4], [1, 2], [5, 6], [8, 3], [2, 7]]

In [43]: sublst = [[1, 2], [8, 3]]

In [44]: [x for x in lst if x not in sublst]
Out[44]: [[3, 4], [5, 6], [2, 7]]

或filter():

In [45]: filter(lambda x:x not in sublst,lst)
Out[45]: [[3, 4], [5, 6], [2, 7]]

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