子串过滤器列表元素由Python中的另一个列表 [英] Substring filter list elements by another list in Python

问题描述

我有两个看起来像这样的列表:

I have two lists looking like:

list1 = ['bj-100-cy','bj-101-hd','sh-200-pd','sh-201-hp']
list2 = [100, 200]

我想用list2的元素对list1进行子字符串过滤，并获得预期的输出，如下所示:

I want to substring filter list1 by elements of list2 and get expected output as follows:

outcome = ['bj-100-cy', 'sh-200-pd']

这样做时:

list1 = str(list1)
list2 = str(list2)
outcome = [x for x in list2 if [y for y in list1 if x in y]]

我得到这样的结果:['[', '1', '0', '0', ',', ' ', '2', '0', '0', ']']. 如何正确过滤?谢谢.

I get a result like this: ['[', '1', '0', '0', ',', ' ', '2', '0', '0', ']']. How can I filter it correctly? Thanks.

与参考相关:

是否可以用Python中的另一个字符串列表过滤子字符串列表?

推荐答案

列表理解和any:

[i for i in list1 if any(i for j in list2 if str(j) in i)]

any检查list2的任何元素是否是要迭代的list1项(__contains__)的子字符串.

any to check if any element of list2 is a substring of the list1 item (__contains__) being iterated over.

示例:

In [92]: list1 = ['bj-100-cy','bj-101-hd','sh-200-pd','sh-201-hp']
    ...: list2 = [100, 200]
    ...: 

In [93]: [i for i in list1 if any(i for j in list2 if str(j) in i)]
Out[93]: ['bj-100-cy', 'sh-200-pd']

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