bash:/bin/ls:参数列表太长 [英] bash: /bin/ls: Argument list too long

问题描述

我需要列出大量文件(40,000个文件)的列表，如下所示:

I need to make a list of a large number of files (40,000 files) like below:

ERR001268_1_100.fastq  ERR001268_2_156.fastq  ERR001753_2_78.fastq
ERR001268_1_101.fastq  ERR001268_2_157.fastq  ERR001753_2_79.fastq
ERR001268_1_102.fastq  ERR001268_2_158.fastq  ERR001753_2_7.fastq
ERR001268_1_103.fastq  ERR001268_2_159.fastq  ERR001753_2_80.fastq

我的命令是:ls ERR*_1_*.fastq |sed 's/\.fastq//g'|sort -n > masterlist 但是错误是:bash: /bin/ls: Argument list too long

my command is: ls ERR*_1_*.fastq |sed 's/\.fastq//g'|sort -n > masterlist However error is: bash: /bin/ls: Argument list too long

但是我可以解决这个问题吗? 还有其他通过perl/python创建列表的方法吗?

However can I solve this problem? Any other way to make list like this by perl/python?

thx

推荐答案

您应该可以将ls ERR*_1_*.fastq替换为find . -name "ERR*_1_*.fastq".
这样，您可以避免将通配符扩展为庞大的参数列表.

You should be able to replace ls ERR*_1_*.fastq with find . -name "ERR*_1_*.fastq".
This way, you can avoid having the wildcard expand into a huge argument list.

(find输出将包含前导"./"，例如./ERR001268_1_100.fastq.如果 这是不希望的，您可以在稍后的版本中使用另一个sed命令将其删除. 管道.)

(The find output will include a leading "./", e.g. ./ERR001268_1_100.fastq . If that's undesirable, you can get rid of it with another sed command later in the pipeline.)

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