获取列表名称 [英] Get the name of a list

问题描述

我不确定是否可以通过简单的方式实现，但是我正在尝试获取列表对象的名称.

I am not sure if this is possible in a simple way, but I am trying to get a name of a list object.

我确实尝试过__name__，但是由于列表对象没有属性__name__

I did try with __name__ but I get an error because the list object does not have an attribute __name__

甚至可以获取列表的变量名称，而无需子类化列表对象并添加__name__属性?

Is even possible to get the variable name for a list, without subclass the list object and add the __name__ attribute?

编辑 这与建议的副本无关.

EDIT This has nothing to do with the suggested duplicate.

这是我的情况:

cucumbers=[]
oranges=[]
salads=[]
...
masterlist=[cucumbers, oranges, salads]

有时我只得到2个列表，而其他时候我得到5个，因此，主列表每次都具有不同数量的列表.当我打印它时，我只得到值；所以我不知道第一名单是黄瓜，橙子，沙拉还是其他.

At times I just get 2 lists, otehr times I get 5, so the masterlist has different number of lists in it, every time; and when I print it, I get only the values; so I don't know if the first list is cucumbers, oranges, salads or whatever it is.

我正在尝试查询列表，以便可以获取variable name，而不是对象的类型.因此print masterlist[1].name会给我黄瓜"或与该列表相关的名称.

I am trying to query the list so I can get the variable name, not the type of the object. so print masterlist[1].name will give me "cucumbers" or whatever is the name associated to that list.

推荐答案

您可以简单地使用字典:

You could simply use a dictionary instead:

masterdict={'cucumbers': cucumbers, 'oranges': oranges, 'salads': salads}

而不是检查名称，而是遍历字典的各项:

And instead of checking the name you iterate over the items of the dictionary:

for name, sublist in masterdict.items():
    print(name, sublist)

如果您希望将其订购(并且您没有Python 3.6，其中订购了dict)则为collections.OrderedDict.

In case you want it ordered (and you don't have Python 3.6 where dicts are ordered) there is collections.OrderedDict.

获取变量名称的问题是变量引用了python对象，但是可以有很多(以不同的名称命名)引用同一对象的变量.同样，对象不需要(可见)名称就可以存在.例如，如果您有类似的东西:

The problem with getting the name for a variable is that variables reference python objects, but there can be many (differently named) variables referencing the same object. Also an object doesn't need a (visible) name to exist. For example if you have something like:

def func():
    cucumber = [1, 2, 3]
    return [cucumber]

然后，函数完成时，名称cucumber不再存在.但是对象([1, 2, 3]列表)仍然存在，但是由于它包装在另一个列表中，因此它甚至不再具有名称".当返回值存储在变量中时，只有外部列表可以有名称.

Then the name cucumber doesn't exist anymore when the function finished. But the object (the [1, 2, 3] list) is still existing, but because it was wrapped in another list it's doesn't even have a "name" anymore. Just the outer list could have a name when the returned value was stored in a variable.

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