平均-Python [英] Average -Python

问题描述

我正在尝试查找范围内数字的平均值(即查找范围1-1000中所有数字的平均值).我编写了以下代码来执行此操作，但是由于if-statement，在运行时，该代码会产生多个数字.然后，我尝试使用while-loop，但是当我输入break语句时，它产生的list与产生的if-statement相同.有什么方法可以使用if-statement并获得1个平均数吗?谢谢！

I am trying to find the average of numbers in ranges (i.e. find the average of all numbers in range 1-1000). I wrote the following code to do this, but the due to the if-statement, when run, the code produces multiple numbers. I then tried a while-loop instead, but when I entered a break statement, it produced the same list the if-statement produced. Is there any way to use an if-statement and get 1 single number that is the average? Thank you!

mylist =[]
def ave_data(x, y):
    for line in filename:    
        for number in line.split():
            if int(number) > x and int(number) < y:
                mylist.append(int(number)) 
                print(sum(mylist)/len(mylist))

推荐答案

由于if语句，它不是 .您只需将print(..)放在for循环的if中.通过将其移动到外部for之外，它将打印整个文件的平均值 :

It is not due to the if statement. You simply put the print(..) in the if in the for loop. By moving it outside the outer for, it will print the average for the entire file:

def ave_data(x, y):
    mylist = []  # move inside
    for line in filename:    
        for number in line.split():
            if int(number) > x and int(number) < y:
                mylist.append(int(number)) 
    print(sum(mylist)/len(mylist))  # for the entire file.

您还可以在功能内 中更好地移动mylist变量.否则，它是一个全局变量，其他函数可以对其进行更改.此外，第二轮运行将取两个文件的平均值.

You also move the mylist variable better inside the function. Otherwise it is a global variable, and other functions can alter it. Furthermore a second run would take the average of the two files.

话虽这么说，您会使事情变得太复杂了.您可以简单地使用:

That being said, you make things too complicated. You can simply use:

def ave_data(x, y):
    mylist = [int(number) for line in filename for number in line.split()
                          if x < int(number) < y]
    print(sum(mylist)/len(mylist))  # for the entire file.

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