从列表中随机选择x个元素 [英] Randomly select x number of elements from a list

问题描述

我正在尝试编写代码，该代码将在列表的1-4个元素之间随机选择50次.我正在使用的列表是['nu', 'ne', 'na', 'ku', 'ke', 'ka'].

I am trying to write a code that will randomly select between 1 and 4 elements of a list 50 times. The list I am working with is ['nu', 'ne', 'na', 'ku', 'ke', 'ka'].

所以从本质上讲，我希望它输出类似的内容

So essentially, I want it to output something like

nukuna
ke
keka
nuka
nane
nanenu
nu
nukekanu
kunu
...

50次

推荐答案

在Python中:

import random

input  = [...] # Your input strings
output = ''

random.seed() # Seed the random generator

for i in range(0,len(input)):
    N = 1+random.randrange(4) # Choose a random number between 1 and 4
    for j in range(0,N): # Choose N random items out of the input
        index = random.randrange(len(input)-j)
        temp = input[index]
        input[index] = input[len(input)-j-1]
        input[len(input)-j-1] = temp
        output += temp
    output += ' '

print output

在C中

#include <stdlib.h>
#include <string.h>
#include <stdio.h>
#include <time.h>

char* input[NUM_OF_INPUT_STRINGS] = {...}; // Your input strings
char output[MAX_SIZE_OF_OUTPUT+1];

// Seed the random generator
srand((unsigned int)time(NULL));

for (int i=0; i<NUM_OF_INPUT_STRINGS; i++)
{
    // Set the output string empty
    output[0] = 0;
    // Choose a random number between 1 and 4
    int N = 1+(rand()%4);
    // Choose N random items out of the input
    for (int j=0; j<N; j++)
    {
        int index = rand()%(NUM_OF_INPUT_STRINGS-j);
        char* temp = input[index];
        input[index] = input[NUM_OF_INPUT_STRINGS-j-1];
        input[NUM_OF_INPUT_STRINGS-j-1] = temp;
        strcat(output,temp);
    }
    // Print the output
    printf("%s ",output);
}

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