NetLogo中的列表差异(从其他列表中省略一个列表) [英] List difference (omit one list from other list) in NetLogo

问题描述

如果我们要在Netlogo中的其他列表中省略一个列表，我们应该如何编写代码? 例如，第一个列表是[1 2 3 4 5] 第二个列表是[4 5] 在这种情况下，应该编写什么代码从列表1中删除列表2，以使新列表包含1、2和3?

In case we want to omit one list from other list in Netlogo , how we should write the code? For example, first list is [1 2 3 4 5] And second list is [4 5] In this case what code should be written to remove list 2 from list 1 so as to having a new list comprises of 1, 2 and 3?

推荐答案

代码:

to-report difference [l1 l2]
  report filter [not member? ? l2] l1
end

示例运行:

observer> show difference [1 2 3 4 5] [4 5]
observer: [1 2 3]
observer> show difference [1 2 3 6] [1 2 3 4 5]
observer: [6]

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