如何为任何给定列表切换元素? [英] How to switch elements for any given list?

问题描述

我说我有一个列表:["5", "6", "4", "3"]

我想做的是用"6"替换任何字符"5"并用"5"替换"6".

What I want to do is replace any char "5" with "6" and replace "6" with "5".

所以列表最后看起来像这样:

So the list would look like this in the end:

["6", "5", "4", "3"]

我要对可能输入的所有列表执行此操作.这意味着并非所有列表中都将包含元素"5"和"6"，但是我想为执行此操作的列表切换5和6.

I want to do this for all lists that may be inputted. This means that not all lists will have the elements "5" and "6" in them, but I want to switch the 5's and the 6's for the lists that do.

注意:列表中的元素是字符串元素.不是整数.

Note: The elements in the list are string elements. Not integers.

我一直在考虑使用if语句和.replace()，但这会更改5和6，但随后又将其更改回去.

I've been thinking of using if statements and .replace() but that changes the 5 and 6, but then changes it back.

示例:

if "5" in list1:
    list1.replace("5", "6")
if "6" in list1:
    list1.replace("6", "5")

如您所见，这只是将其替换回来.它不起作用.如果有人可以帮助我解决这个问题，那就太好了.

As you can see, that just replaces it back. It doesn't work. It would be great if someone could help me solve this.

注意:如果元素在列表中为"1532"，则该元素中的5也应替换为字符串.反之亦然..

Note: If the element is "1532" in a list, the 5 in that should also be replaced with a string. Vice versa for 6's as well.

另一个示例:

firstlist = ["125", "673", "222", "65"]`

输出:

firstlist = ["126", "573", "222", "56"]

推荐答案

在假设列表中没有下划线和制表符的情况下，这可以起作用:

Under the assumption there are no underscores and tabs in your lists, this can work:

>>> list1 = ["126", "573", "222", "56"]
>>> str1 = "\t".join(list1)
>>> str1.replace("5", "_").replace("6", "5").replace("_", "6").split('\t')
['125', '673', '222', '65']

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