在Python中初始化列表的第一个索引 [英] Initialize the first index of a list in Python

问题描述

我正在将用C ++编写的内容转换为Python.这是我要用python重写的代码片段:

I am converting something I wrote in C++ to Python. Here is a snippet of what I am trying to rewrite in python:

std::vector<int> dates(numberOfPayments.size(), 0);
dates[0] = NDD[0] - '0';
for (int i = 1; i < dates.size(); ++i)
{
    dates[i] = (dates[i - 1] + 12 - numberOfPayments[i - 1]) % 12;
}

我遇到的问题是我无法将python中列表的第一个索引设置为某些值.我尝试这个:

The problem I am having is that I cannot set the first index of my list in python to something. I try this:

dates = []
dates[0] = NDD_month[0]
for i in range(len(first_payments)):
    dates[i] = (dates[i-1] + 12 - first_payments[i-1]) % 12
print(dates)

但是我得到这个错误:

IndexError: list assignment index out of range

有人知道如何解决这个问题吗?

Anyone know how to fix this?

推荐答案

您遇到了此问题，因为您试图访问尚未分配的索引.

You're having this problem because you're trying to access a index that was not allocated yet.

要将内容附加到列表中，应使用append(已修改以修复循环):

To append things to a list you should use append (edited to fix loop):

dates = []
dates.append(NDD_month[0])
for i in range(1, len(first_payments)):
    dates.append((dates[i-1] + 12 - first_payments[i-1]) % 12)
print(dates)

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