如何在Python中以数学方式减去两个列表中的项目并仅输出满足条件的项目? [英] How to mathematically subtract items in two lists in Python and only output those items which meet a condition?

问题描述

我有两个列表已经从低到高排序:

I have two lists that are already sorted from low to high:

A=['40','60','80']

B=['10','42','100']

我想用B中的每个项目减去A中的每个项目.然后，如果这些值之间的差满足一个条件，特别是如果小于5，则从输出应为以下内容的每个列表中删除这两个项目:

I want to subtract each item in A by every item in B. Then, if the difference between these values meets a condition, specifically, if less than 5, then delete both items from each list where the output should be:

A=['60','80']
B=['10','100']

**有时列表的长度不相等，有时每个列表中只有1个项目

**Sometimes lists are unequal in length, and sometimes there are only 1 item in each list

我找到了许多方法来减去列表中的项目，但是我不知道如何检索和删除指定列表中的特定项目，或者它们仅从相反列表中的每个对应项目中减去一项.

I have found many ways to subtract items in lists, but I do not know how to retrieve and delete the specific items in the specified lists, or they only subtract one item from each corresponding item in the opposite list

使用lambda:

如果list(imap(lambda m，n:m-n< 5，A，B))==真:

if list(imap(lambda m, n: m-n < 5, A, B)) == True:

使用imap，sub

Using imap,sub

list(imap(sub, A, B)):

使用Numpy

M = np.array([A])

N = np.array([B])

c = abs(M-N)

非常感谢.

推荐答案

不使用numpy:

A = ["40", "60", "80"]

B = ["10", "42", "100"]

newA = filter(lambda a: all([abs(int(a) - int(b)) >= 5 for b in B]), A)
newB = filter(lambda b: all([abs(int(a) - int(b)) >= 5 for a in A]), B)

print newA
print newB

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