计算Python字符串的唯一字符总数 [英] Counting total number of unique characters for Python string

问题描述

对于上述问题，我深陷其中.到目前为止，我想出的代码是:

For my question above, I'm terribly stuck. So far, the code I have come up with is:

def count_bases():
    get_user_input()
    amountA=get_user_input.count('A')
    if amountA == 0:
        print("wrong")
    else:
        print ("right",amountA)

def get_user_input():
    one = input("Please enter DNA bases: ")
    two=list(one)
    print(two)

我的思路是我首先:
1.要求用户输入DNA碱基(ATCG)
2.将用户输入更改为列表
3.回到主要(count_bases)函数，我计算'A'，'T'，'C'，'G'的数量
4.对4个不同的基数使用4条if-else语句.

My line of thinking is that I first:
1. Ask user to enter the DNA bases (ATCG)
2. Change the user input into a list
3. Going back to the main (count_bases) function, I count the number of 'A', 'T', 'C', 'G'
4. Use 4 if-else statements for the four different bases.

到目前为止，我的代码仅适用于列表中用户输入的输出.之后，会弹出一个错误.
如果有人可以向我指出正确的道路，请多加赞赏！
谢谢.

So far, my code only works up to the output of the user's input into a list. After that, an error just pops up.
Appreciate it if someone can point the right path out to me!
Thanks.

推荐答案

1. 您的函数get_user_input()没有返回值
2. get_user_input.count('A')包含一个函数调用，如果没有括号，它将无法使用.正确:get_user_input().count('A')
3. 如评论中所述，get_user_input()仅应调用一次，因为用户输入将通过input()函数在每次调用时收集.

1. Your function get_user_input() has no return value
2. get_user_input.count('A') contains a function call, it will not work without parenthesis. Correct: get_user_input().count('A')
3. As mentioned in the comments, get_user_input() should only be called once since the users input will be collected at each call via the input() function.

这应该有效:

    def count_bases():
        char_list = get_user_input()
        for char in 'ATCG':
            char_count = char_list.count(char)
            if char_count < 1:
                print(char + " not found")
            else:
                print(char + " count: " + str(char_count))

    def get_user_input():
        one = input("Please enter DNA bases: ")
        two=list(one)
        return two

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