显示有和没有排序的ArrayList? [英] Displaying an ArrayList with and without sorting?
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问题描述
可能重复:
排序的ArrayList不显示?
Possible Duplicate:
Sorted ArrayList not displaying?
代码:
String title1 = "Original Order\n\n";
String title2 = "Sorted Order\n\n";
String collection = "";
for (int i = 0; i < cdcollection.size(); i++) {
collection = collection + cdcollection.get(i);
}
mainTextArea.setText(title1 + collection);
Collections.sort(cdcollection);
String temp = "";
for (int j = 0; j < cdcollection.size(); j++) {
temp += cdcollection.get(j);
}
mainTextArea.setText(title2 + temp);
推荐答案
我带了您的代码,但未添加任何代码,并且列表已正确排序.参见下面的代码
I took your code without the swing code and the list is sorted properly. See the code below
public static void main(String[] args){
ArrayList<String> cdcollection = new ArrayList();
Collections.addAll(cdcollection, "renier\n", "mert\n", "rain\n",
"mylen", "dreb\n");
String title1 = "Original Order\n\n";
String title2 = "Sorted Order\n\n";
String collection = "";
for (int i = 0; i < cdcollection.size(); i++) {
collection = collection + cdcollection.get(i);
}
System.out.println(title1 + collection);
Collections.sort(cdcollection);
System.out.println(cdcollection);
}
您在此处使用的for循环
The for loop you used here
for (int j = 0; j < cdcollection.size(); j++) {
mainTextArea.setText(title2 + collection.get(j));
}
不要在循环中添加title2
,并且在循环中调用setText将覆盖旧文本.将列表中的所有字符串添加到临时字符串中,并添加到mainTextArea
中最后一个字符串中.像
Dont add the title2
in the loop and calling setText in loop will over write the old text. Append all the string from the list in a temp string and in the last set in the in the mainTextArea
. Something like
String temp = "";
for (int j = 0; j < cdcollection.size(); j++) {
temp += cdcollection.get(j));
}
mainTextArea.setText(title2 + temp);
但是,正如亚历山大所提到的,这绝对是重复的.您本可以编辑相同的问题.
But this is definitely a duplicate as mentioned by Alexander. you could have edited the same question.
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