将字典中的关键字与Python中的列表匹配 [英] Matching keywords in a dictionary to a list in Python

问题描述

以下字典给出了单词及其值:

The following dictionary gives the word and its value:

keywords = {'alone': 1, 'amazed': 10, 'amazing': 10, 'bad': 1, 'best': 10, 'better': 7, 'excellent': 10, 'excited': 10, 'excite': 10}

在字典后的列表中，有两条推文. 对于每条推文，我们需要从中找到关键字中的哪些单词.

Following the dictionary are two tweets in a list in a list. For each tweet, we need to find which of the words from keywords are present in it.

tweets = [['work', 'needs', 'to', 'fly', 'by', '', "i'm", 'so', 'excited', 'to', 'see', 'spy', 'kids', '4', 'with', 'then', 'love', 'of', 'my', 'life', '', 'arreic'], ['today', 'is', 'going', 'to', 'be', 'the', 'greatest', 'day', 'of', 'my', 'life', 'hired', 'to', 'take', 'pictures', 'at', 'my', 'best', "friend's", 'gparents', '50th', 'anniversary', '60', 'old', 'people', 'woo']] 

目标是找到在每个推文行中找到的关键字值总和.

The target is to find the sum of the keyword values found in each tweet line.

创建的代码需要循环，因为有2条以上的推文. 我不知道如何执行此过程.

The code created needs to be a loop because there are more than 2 tweets. I do not understand how I should execute this process.

感谢您的见识！

推荐答案

尝试一下:

keywords = {'alone': 1, 'amazed': 10, 'amazing': 10, 'bad': 1, 'best': 10, 'better': 7, 'excellent': 10, 'excited': 10, 'excite': 10}
tweets = [['work', 'needs', 'to', 'fly', 'by', '', "i'm", 'so', 'excited', 'to', 'see', 'spy', 'kids', '4', 'with', 'then', 'love', 'of', 'my', 'life', '', 'arreic'], ['today', 'is', 'going', 'to', 'be', 'the', 'greatest', 'day', 'of', 'my', 'life', 'hired', 'to', 'take', 'pictures', 'at', 'my', 'best', "friend's", 'gparents', '50th', 'anniversary', '60', 'old', 'people', 'woo']]
total = 0

for i in keywords:
    for j in tweets:
        if i in j:
            occourance = j.count(i)
            print('keyword=', i)
            total += keywords[i]*occourance
print('sum is: ', total)




output:  
    keyword= best
    keyword= excited
    sum is:  20

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