获取< generator对象< genexpr> [英] Getting <generator object <genexpr>

问题描述

我有2个列表:

first_lst = [('-2.50', 0.49, 0.52), ('-2.00', 0.52, 0.50)]
second_lst = [('-2.50', '1.91', '2.03'), ('-2.00', '1.83', '2.08')]

我想对它做以下数学运算:

I want to do the following math to it:

将0.49乘以1.91(对应于first_lst和second_lst的值)，然后将0.52乘以2.03(也对应相应的值).我想在每个对应元组的位置0上的值都是偶数的情况下执行此操作，因此-2.50 == -2.50等.显然，我们还对剩余元组进行了相同的数学运算.

Multiply 0.49 by 1.91 (the corresponding values from first_lst and second_lst), and multiply 0.52 by 2.03 (corresponding values also). I want to do that under condition that values at position 0 in each corresponding tuple is idential so -2.50 == -2.50 etc. Obviously, we do the same math for remaning tuples as well.

我的代码:

[((fir[0], float(fir[1])*float(sec[1]), float(fir[2])*float(sec[2])) for fir in first_lst) for sec in second_lst if fir[0] == sec[0]]

但是生成一些对象:

[<generator object <genexpr> at 0x0223E2B0>]

您能帮我解决代码吗?

Can you help me fix the code?

推荐答案

您需要使用tuple()或list()将该生成器表达式转换为list或tuple:

You need to use tuple() or list() to convert that generator expression to a list or tuple:

[tuple((fir[0], fir[1]*sec[1], fir[2]*sec[2]) for fir in first_lst)\
                               for sec in second_lst if fir[0] == sec[0]]

您的代码的工作版本:

>>> first_lst = [tuple(float(y) for y in x) for x in first_lst]
>>> second_lst = [tuple(float(y) for y in x) for x in second_lst]

>>> [((fir[0],) + tuple(x*y for x, y in zip(fir[1:], sec[1:]))) \
                  for fir in first_lst for sec in second_lst if fir[0]==sec[0]]
[(-2.5, 0.9359, 1.0555999999999999), (-2.0, 0.9516000000000001, 1.04)]

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