Python列表理解，具有唯一项 [英] Python list comprehension, with unique items

问题描述

有没有办法在仅包含唯一项的Python中进行列表理解?

Is there a way to make a list comprehension in Python that only contains unique items?

我最初的想法是使用这样的东西: new_items = [unicode(item) for item in items]

My original idea was to use something like this : new_items = [unicode(item) for item in items]

但是，我后来意识到我需要省略重复的项目.所以我结束了这个丑陋的怪物:

However, I later realized that I needed to omit duplicate items. So I ended up with this ugly monstrosity :

unique_items = []
for item in items :
    unicode_item = unicode(item)
    if unicode_item not in unique_items :
        unique_items.append(unicode_item)

现在，这比简单的列表理解要简单得多(而且可读性强).那么，有没有办法使列表理解等同于上面的代码?

Now this is far less pretty (and readable) than a simple list comprehension. So, is there a way to make a list comprehension equivalent to the above code?

顺序也很重要，所以我不能只使用集合理解.

Also order does matter, so I can't just use a set comprehension.

推荐答案

好，没有有序集，但是我们可以误用OrderedDict:

Well, there is no ordered set, but we can misuse OrderedDict:

from collections import OrderedDict
t = "never gonna give you up"
OrderedDict.fromkeys(t).keys()

赠予:

['n', 'e', 'v', 'r', ' ', 'g', 'o', 'a', 'i', 'y', 'u', 'p']

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