重复的联系人不显示在listiview中 [英] duplicate contacts not to show in listiview

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本文介绍了重复的联系人不显示在listiview中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在制作一个可在Listview中显示联系人号码的应用程序,但它却给出了重复的联系人条目,我只想单独显示一个联系人

i am making an app to show contacts number in a Listview but it is giving duplicate contacts entries i wanted to only show one contact singly

 private void getContactList() {
    ContentResolver cr = getContentResolver();
    Cursor cur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");

    if ((cur != null ? cur.getCount() : 0) > 0) {
        while (cur != null && cur.moveToNext()) {
            String id = cur.getString(
                    cur.getColumnIndex(ContactsContract.Contacts._ID));
            String name = cur.getString(cur.getColumnIndex(
                    ContactsContract.Contacts.DISPLAY_NAME));

            if (cur.getInt(cur.getColumnIndex(
                    ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0) {
                Cursor pCur = cr.query(
                        ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                        null,
                        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
                        new String[]{id}, null);
                while (pCur.moveToNext()) {
                    String phoneNo = pCur.getString(pCur.getColumnIndex(
                            ContactsContract.CommonDataKinds.Phone.NUMBER));
                    ContactsPlacer obj = new ContactsPlacer();
                    obj.setContactname(name);
                    obj.setContactnumber(phoneNo);
                    names.add(obj);

                }
                pCur.close();
            }
        }
    }
    if(cur!=null){
        cur.close();
    }




}

帮我解决一下,重复的联系人不在列表视图中显示

help me about it that the duplicate contacts not show in listview

推荐答案

boolean checkexsistance(ContactsPlacer obj)
{
boolean test= true;
for(int i = 0 ; i<names.size();i++)
{
if(names.get(i).getContactname().equals(obj.getContactname()))
{
    test = false;
    break;

}

}


return test;
}



private void getContactList() {
    ContentResolver cr = getContentResolver();
    Cursor cur = cr.query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC");

    if ((cur != null ? cur.getCount() : 0) > 0) {
        while (cur != null && cur.moveToNext()) {
            String id = cur.getString(
                    cur.getColumnIndex(ContactsContract.Contacts._ID));
            String name = cur.getString(cur.getColumnIndex(
                    ContactsContract.Contacts.DISPLAY_NAME));

            if (cur.getInt(cur.getColumnIndex(
                    ContactsContract.Contacts.HAS_PHONE_NUMBER)) > 0) {
                Cursor pCur = cr.query(
                        ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
                        null,
                        ContactsContract.CommonDataKinds.Phone.CONTACT_ID + " = ?",
                        new String[]{id}, null);
                while (pCur.moveToNext()) {
                    String phoneNo = pCur.getString(pCur.getColumnIndex(
                            ContactsContract.CommonDataKinds.Phone.NUMBER));


                    ContactsPlacer obj = new ContactsPlacer();
                    obj.setContactname(name);
                    obj.setContactnumber(phoneNo);
                    if(checkexsistance(obj))
                       names.add(obj);

                }
                pCur.close();
            }
        }
    }
    if(cur!=null){
        cur.close();
    }




}

这篇关于重复的联系人不显示在listiview中的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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