创建适用于Android的直播应用 [英] Create a Live Streaming APP for Android

问题描述

我最近遇到了麻烦.

我想开发一个嵌入了实时流的Android App，但我只是不知道如何开始. 我尝试使用嵌入了livestreaming标签的Webview，但是它不起作用(很可能是通过Flash提供流的). 我也尝试过使用VideoView组件，但是它也没有用.

I want to develop an Android App with a livestreaming embeded, but I just don't know how to start. I tried using an Webview with the livestreaming tag embeded, but it didn't work (most likely the stream is provided via Flash). I also tried to use a VideoView component but it also didn't work.

我知道这是有可能的，因为那些发布者拥有自己的APP，但是我们提供的格式通常是Flash.不是移动友好格式.

I know it's possible because those publishers have their own APP, but the format we are provided is usually Flash. Not a mobile friendly format.

请有人告诉我有关如何开始或是否有解决方法的任何想法吗?

Can someone, please, show me any idea on how to start or if there is some workaround?

提前谢谢！

我想做的是，例如，以这个流为例: http://new.livestream.com/ATP/lexington2014court1 并显示在我的APP中.

What I would like to do is, like, take this stream, for example: http://new.livestream.com/ATP/lexington2014court1 and show it inside my APP.

推荐答案

我认为我做到了！

首先，我确实使用了livestream.com上的流，但是现在，他们没有实际版本的公共API，但是.... 我从这里得到了很多帮助: new.livestream.com API以获得RTSP

First of all, I am indeed using the stream from livestream.com, but right now, they don't have a public API to the actual version, but.... I got a lot of help from here: new.livestream.com API to get RTSP

因此，有此API调用 http://new.livestream.com/api/accounts /[account_id]/events/[event_id]/viewing_info

So, there is this API call http://new.livestream.com/api/accounts/[account_id]/events/[event_id]/viewing_info

这将向我们返回JSON.然后，我将"rtsp_url"值放入我的VideoURI中.

which return us a JSON. Then, I take the "rtsp_url" value and put it into my VideoURI.

所以这是我的代码: 请用上面获取的JSON中的"rtsp_url"的值替换下面代码中的"{VIDEO_RTSP_URL}".

So here it goes my code: Please, replace "{VIDEO_RTSP_URL}" in the code below with the value of the "rtsp_url" from the JSON you got above.

MainActivity.java

MainActivity.java

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    VideoView videoView = (VideoView) findViewById(R.id.video);
    MediaController mediaController = new MediaController(this);
    mediaController.setAnchorView(videoView);
    mediaController.setMediaPlayer(videoView);

    Uri video = Uri.parse("{VIDEO_RTSP_URL}");
    videoView.setMediaController(mediaController);
    videoView.setVideoURI(video);
    videoView.start();      
}

activity_main.xml

activity_main.xml

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    android:paddingBottom="@dimen/activity_vertical_margin"
    android:paddingLeft="@dimen/activity_horizontal_margin"
    android:paddingRight="@dimen/activity_horizontal_margin"
    android:paddingTop="@dimen/activity_vertical_margin"
    tools:context="com.fcl.videoplay.MainActivity" >

    <VideoView
        android:id="@+id/video"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:layout_alignParentBottom="true"
        android:layout_alignParentLeft="true"
        android:layout_alignParentRight="true"
        android:layout_alignParentTop="true" />

</RelativeLayout>

现在，由于某种原因，当我连接到Wi-Fi时，流媒体无法正常工作，但是当我使用3G时(我正在实际设备上进行测试.不是仿真器)，它可以正常工作，但这是另一个主题

Now, for some reason, the streaming is not working when I connect to the Wi-Fi, but it works when I am on 3G (I am testing on a real device. Not an emulator), but this is another topic

总体而言，如果您正在使用Livestream.com之类的流媒体服务，则它们可能会通过API为您提供类似RTSP_URL的内容.您可能只需要使用它即可.

Overall, if you're using a streaming service, like Livestream.com, they might provide you something like this RTSP_URL via an API. You will likely just need to use it.

这篇关于创建适用于Android的直播应用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！