Xcode中省略参数的高级本地化 [英] Advanced Localization with Omission of Arguments in Xcode

问题描述

我有一个正在翻译的格式化字符串.

I have this formatted string that I am having a translator work on.

ENGLISH

ENGLISH

"Check out the %1$@ %2$@ in %3$@: %4$@" = "Check out the %1$@ %2$@ in %3$@: %4$@"

德语翻译

"Check out the %1$@ %2$@ in %3$@: %4$@" = "Hör Dir mal %2$@ in %3$@ an: %4$@";

这些将传递给[NSString stringWithFormat:]调用:

//////////////////////////////////////
// Share Over Twitter
NSString *frmt = NSLocalizedString(@"Check out the %1$@ %2$@ in %3$@: %4$@", @"The default tweet for sharing sounds. Use %1$@ for where the sound type (Sound, mix, playlist) will be, %2$@ for where the audio name will be, %3$@ for the app name, and %3$@ for where the sound link will be.");
NSString *urlString = [NSString stringWithFormat:@"sounds/%@", SoundSoundID(audio)];
NSString *url = ([audio audioType] == UAAudioTypeSound ? UrlFor(urlString) : APP_SHORTLINK);
NSString *msg = [NSString stringWithFormat:
                 frmt,
                 [[Audio titleForAudioType:[audio audioType]] lowercaseString],
                 [NSString stringWithFormat:@"\"%@\"", AudioName(audio)],
                 APP_NAME, 
                 url];
returnString = msg;

预期的和实际的结果:

ENGLISH

ENGLISH

desired: "Check out the sound "This Sound Name" in My App Name: link_to_sound"
actual:  "Check out the sound "This Sound Name" in My App Name: link_to_sound"

德语

desired: "Hör Dir mal "This Sound Name" in My App Name an: link_to_sound"
actual:  "Hör Dir mal sound in "This Sound Name" an: My App Name"

问题 问题是，我的假设是，通过在-[NSString stringWithFormat:]中使用带编号的变量，我可以做这样的事情，其中​​%1$@变量被完全省略了.如果您注意到，格式字符串的德语翻译根本不使用第一个参数(%1$@)，但是它(声音")仍会出现在输出字符串中.

THE PROBLEM The problem is that I was under the assumption that by using numbered variable in the -[NSString stringWithFormat:], I could do things like this, where the %1$@ variable is completely omitted. If you notice, the German translation of the format string does not use the first argument (%1$@) at all but it ("sound") still appears in the output string.

我在做什么错了?

推荐答案

这不是错误.带编号的参数不是C标准的一部分，而是IEEE Std 1003.1的一部分，它表示以下内容(强调我的意思):

This is not a bug. Numbered arguments are not part of the C standard, but part of IEEE Std 1003.1, which says the following (emphasis mine):

格式可以包含带编号的参数转换规范(即％n $"和"* m $")，也可以包含无编号的参数转换规范(即％和*)，但不能同时包含两者.唯一的例外是%%可以与％n $"形式混合使用.在格式字符串中混合编号和未编号的参数说明的结果是不确定的. 使用带编号的参数规范时，指定第N个参数要求在格式字符串中指定所有从第一个到第(N-1)个前导参数.

The format can contain either numbered argument conversion specifications (that is, "%n$" and "*m$"), or unnumbered argument conversion specifications (that is, % and * ), but not both. The only exception to this is that %% can be mixed with the "%n$" form. The results of mixing numbered and unnumbered argument specifications in a format string are undefined. When numbered argument specifications are used, specifying the Nth argument requires that all the leading arguments, from the first to the (N-1)th, are specified in the format string.

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