C#返回局部变量 [英] C# Returning local variables

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本文介绍了C#返回局部变量的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

来自C ++,返回局部变量是个坏主意(在堆栈上分配内存时).

Coming from C++, returning a local variable was a bad idea (when allocated memory on the stack).

现在使用C#的印象是,这不是一个坏主意(返回值而不是引用时).

Now using C# I'm getting the impression it isn't a bad idea (when returning a value, not a reference).

那是为什么?我知道C#使用GC,但是我不确定在这种情况下会有什么区别.

Why is that? I understand C# uses the GC but I'm not sure what difference that would make in this case.

推荐答案

C/C ++中的问题是您可以返回指向堆栈上数据的指针.如果这样做,则一旦堆栈帧被破坏,指针就无效.在托管C#中,您无法执行此操作.

The problem in C/C++ is that you can return a pointer to data that is located on the stack. If you do that the pointer is invalid as soon as the stack frame is destroyed. In managed C# you can't do such a thing.

使用C#返回本地人很好.如果返回值类型,则将复制该值.如果返回引用,则引用本身将被复制(但仍指向堆上的同一对象).无论哪种情况,都没有问题.

Returning locals in C# is fine. If you return a value type, the value is copied. If you return a reference, the reference itself is copied (but it still points to the same object on the heap). In either case, there's no issue.

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