排序与另一组ID匹配的对象的数组 [英] Sorting array of objects matching ids on a different set

问题描述

我有一个对象数组

array = [
    {id: 5, name: "Helen", age: 20}, 
    {id: 15, name: "Lucy", age: 30}, 
    {id:7, name: "Carlos", age: 1}
]

然后我有一个类似的数组，但排序不同

Then I have a similar array sorted differently

arraySorted = [        
    {id: 15, name: "Lucy", age: 2}, 
    {id: 5, name: "Lara", age: 11}, 
    {id:7, name: "Carlos", age: 10}
]

两个数组上的对象ID始终匹配，其余属性可能相同也可能不相同.

The ids of the objects on both arrays will always match, the rest of the properties may or may not.

我需要按照与arraySorted相同的id顺序对数组进行排序.

What I need is sorting the array in the same id order as arraySorted.

(也可以在普通的JavaScript上完成，lodash不是必需的，但也许会有用)

(it can be also done on plain JavaScript, lodash is not necessary but maybe it will be useful)

推荐答案

而不是sort，而是使用map，find和Object.assign

Rather than sort, use map, find and Object.assign instead

arraySorted.map( s => Object.assign( s, array.find( t => t.id == s.id ) ) );

演示

var array = [{
    id: 5,
    name: "Helen",
    age: 20
  },
  {
    id: 15,
    name: "Lucy",
    age: 30
  },
  {
    id: 7,
    name: "Carlos",
    age: 1
  }
];
var arraySorted = [{
    id: 15,
    name: "Lucy",
    age: 2
  },
  {
    id: 5,
    name: "Lara",
    age: 11
  },
  {
    id: 7,
    name: "Carlos",
    age: 10
  }
];
array = arraySorted.map(s => Object.assign(s, array.find(t => t.id == s.id)));

console.log(array);

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