如何将uuid添加到log4j以登录文件? [英] How to add uuid to log4j for logging into file?

问题描述

我有这个log4j2.xml文件:

I have this log4j2.xml file:

<?xml version="1.0" encoding="UTF-8"?>
<Configuration xmlns="http://logging.apache.org/log4j/2.0/config">
<Appenders>
    <File name="FILE" fileName="logfile.log" append="true">
        <PatternLayout pattern="%p | [%t] %l | message : %m%n"/>
    </File>
    <Console name="STDOUT" target="SYSTEM_OUT">
        <PatternLayout pattern="%p | [%t] %l | message : %m%n"/>
    </Console>
</Appenders>
</Configuration>

我的目标是使用uuid在RestEndpoint中添加唯一的ID，但是我不知道如何添加到xml文件中...或者我必须不在xml文件中进行配置?

And my goal is to add in the RestEndpoint a unique id with uuid, but i dont know how to add to the xml file...or i have to configure it not in an xml file?

推荐答案

在您的应用程序中，将uuid放入ThreadContext:

In your application, put the uuid in the ThreadContext:

ThreadContext.put("myUuid", new UUID());

我假设您知道应用程序中的入口点在哪里放置和删除这些入口点.

I assume you know where the entry points in your application are where to put and remove these.

在配置中，使用%X模式转换器从ThreadContext中提取UUID:(还将Loggers添加到您的配置中)

In configuration, extract the UUID from the ThreadContext with the %X pattern converter: (also added Loggers to your configuration)

<?xml version="1.0" encoding="UTF-8"?>
<Configuration status="warn">
<Appenders>
    <File name="FILE" fileName="logfile.log" append="true">
        <PatternLayout pattern="%p | [%t] %l | id: %X{myUuid} | message : %m%n"/>
    </File>
    <Console name="STDOUT" target="SYSTEM_OUT">
        <PatternLayout pattern="%p | [%t] %l | id: %X{myUuid} | message : %m%n"/>
    </Console>
</Appenders>

<Loggers>
  <Root level ="trace">
    <AppenderRef ref="STDOUT" />
    <AppenderRef ref="FILE" />
  </Root>
</Loggers>
</Configuration>

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