我想在日志语句中显示文件名 [英] I want to display the file Name in the log statement

查看:95
本文介绍了我想在日志语句中显示文件名的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

对于任何级别的每个logger语句,我需要显示执行log语句的文件名,下面是我在下面给出的插图:

For every logger statement with any level, I need to display the file name from where the log statement executed, below is the illustration I given below:

示例: 下面是从 JobWork.js

logger.info("getInCompleteJobs in job works");

实际:

2012-11-05T06:07:19.158Z - info: getInCompleteJobs in job works

必填:

2012-11-05T06:07:19.158Z - info JobWork.js : getInCompleteJobs in job works

在不从日志语句中传递fileName作为参数的情况下,它应该提供文件名.

Without passing the fileName as a parameter from the log statement it should give the filename.

推荐答案

您可以使用附加到v8的Error对象的堆栈跟踪信息来查找调用代码的文件/行.这种方法行之有效,但效果不佳.因此,如果您在开发过程中使用它,则在生产时将要禁用它.

You can use the stack trace information attached to v8's Error object to find out what file/line your code was called from. This approach works well, but it does not perform well; so if you use it during development, you will want to disable it when you go to production.

因此您可以执行以下操作:

So you could do something like this:

  var logger_info_old = logger.info;
  logger.info = function(msg) {
    var fileAndLine = traceCaller(1);
    return logger_info_old.call(this, fileAndLine + ":" + msg);
  }

  /**
  * examines the call stack and returns a string indicating 
  * the file and line number of the n'th previous ancestor call.
  * this works in chrome, and should work in nodejs as well.  
  *
  * @param n : int (default: n=1) - the number of calls to trace up the
  *   stack from the current call.  `n=0` gives you your current file/line.
  *  `n=1` gives the file/line that called you.
  */
  function traceCaller(n) {
    if( isNaN(n) || n<0) n=1;
    n+=1;
    var s = (new Error()).stack
      , a=s.indexOf('\n',5);
    while(n--) {
      a=s.indexOf('\n',a+1);
      if( a<0 ) { a=s.lastIndexOf('\n',s.length); break;}
    }
    b=s.indexOf('\n',a+1); if( b<0 ) b=s.length;
    a=Math.max(s.lastIndexOf(' ',b), s.lastIndexOf('/',b));
    b=s.lastIndexOf(':',b);
    s=s.substring(a+1,b);
    return s;
  }

这篇关于我想在日志语句中显示文件名的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆