获取日志输出的行号和文件名 [英] get line number and filename for a log output

问题描述

是否可以获取每个日志输出的行号和文件?

Is it possible to get the line number and file for each log output ?

例如:

  var winston = require('winston');

  winston.log('info', 'some message!'); // this is at line 4 of myfile.js

应在日志文件中指定某些消息"来自myFile.js第4行.

should specify in log file that 'some message' came from myFile.js line 4.

推荐答案

您可以将文件名传递为label，并且可以从调用模块中获取文件名.

You can pass the file name as label and you can get the file name from callingModule.

创建logger.js文件和类似的代码

var winston = require('winston');
var getLabel = function (callingModule) {
    var parts = callingModule.filename.split('/');
    return parts[parts.length - 2] + '/' + parts.pop();
};

module.exports = function (callingModule) {
    return new winston.Logger({
        transports: [
            new winston.transports.Console({
                label: getLabel(callingModule),
                json: false,
                timestamp: true,
                depth:true,
                colorize:true
            })
        ]
    });
};

现在这是您的测试文件

var logger = require('./logger')(module);
function test() {
    logger.info('test logger');
}
test();

如果您运行测试文件，则输出看起来像

and if you run test file than the output looks like

2017-07-08T07:15:20.671Z - info: [utils/test.js] test logger

这篇关于获取日志输出的行号和文件名的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！