PHP相交数组而不是NULL数组 [英] PHP Intersect Array but not NULL Array

问题描述

我有五个二维数组(您可以假设它像五个电子表格一样)，我想取五个的交集(我想要一个新电子表格中所有五个的共同行)，但是现在我发现了数组之一是NULL数组，(我发现它不是电子表格，而只是一张空白的纸)，所以现在我想忽略它并与其余的数组相交...请建议一种方法那...

I have five 2-D Arrays, (You can assume it like five spreadsheets), I want to take the intersection of the five (I want the common rows of all five in a new spreadsheet) but now I find out that one of the array is a NULL Array, (I find that instead of a spreadsheet, it's just a blank piece of paper), so now I want to ignore it and Intersect the rest of the Arrays... Please suggest a method of doing that...

P.S. -我知道这与交集的性质相反，因为我们都知道带有NULL的任何事物的交集都是NULL，但这不是我想要的...

P.S. - I know it is against the property of intersection because we all know that Intersection of anything with NULL is NULL, but that is not what I want...

P.S. -我也不知道有多少个数组可以为空，我只是假设它为1，可以为2、3、4或什至5 ...是的，如果为5，则返回NULL是完美，但在任何其他情况下都不行...假设4个数组为NULL，则它应该返回第5个数组...

P.S. - I also don't know how many Arrays can be empty, I just assumed it to be 1 as an Example, It can be 2, 3, 4 or Even 5... Yes, If it is 5, then returning NULL is perfect but not in any other case... Suppose if 4 Arrays are NULL, then It should return the 5th Array...

使用的语言:PHP

推荐答案

您可以使用 array_filter()和 in_array() >检查您的数组是否为空

You can use array_filter() and a custom implementation of in_array() to check if your array is null

解决方案:

$array1 = array(6,  10, 11, 12);
$array2 = array(6, 741, 18, 9, 110, 11, 12);
$array3 = array(8, 10, 11, 20);
$array4 = null;
$array5 = array(9, 10, 11, 12);


function in_array_custom($item, $array)
{
    if($array === null){
        return true;
    }
    return in_array($item, $array);
}

function intersect($item)
{
    global $array2;
    global $array3;
    global $array4;
    global $array5;
    return in_array_custom($item, $array2) && in_array_custom($item, $array3) && in_array_custom($item, $array4) && in_array_custom($item, $array5);
}

print_r(array_filter($array1, "intersect")); 

在线示例

我分享了全局解决方案:

I share the global solution :

<?php

$arrays = array(
    array(6,  10, 11, 12),
    array(6, 741, 18, 9, 110, 11, 12),
    array(8, 10, 11, 20),
    null,
    array(9, 10, 11, 12)
);

function in_array_custom($item, $array)
{
    if($array === null){
        return true;
    }
    return in_array($item, $array);
}

function in_arrays($item, $arrays)
{
    foreach($arrays as $array)
    {
        if(!in_array_custom($item, $array)) {
            return false;
        }
    }
    return true;
}

function intersect($item)
{
    global $arrays;
    return in_arrays($item, $arrays);
}

print_r(array_filter($arrays[0], "intersect"));

在线示例

这里，有一个小问题，如果第一个数组($array1)为空，则代码将不起作用，但是可以通过将$array1作为所有SIX数组的并集来解决该问题. ，(5个数组和1个联合数组)，然后将数据移至下一个数组，即$array2现在保存了$array1，$array3 = $array2等数据……

Here, there is one little issue, that If the first array ($array1) is null, then the code will not work, but that issue can be resolved by taking $array1 as a Union of all the SIX Arrays, (5 Arrays and 1 Union Array), And the Data is shifted to the next array, i.e $array2 now holds the data of $array1, $array3 = $array2 and so on...

P.S. -数组联合可以像这样$array1 = $array2 + $array3 + $array4 + $array5 + $array6;

P.S. - Union of Arrays can be done like this $array1 = $array2 + $array3 + $array4 + $array5 + $array6;

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