具有逻辑或的IF语句 [英] IF statement with logical OR

问题描述

if(1 == 2 || 4)
{
cout<<"True";
}
else
{
cout<<"False";
}

这就是我阅读以上内容的方式.如果1等于2或4，则打印true.否则，打印false.当执行此命令时，将打印true.显然我在这里误会了一些东西. 1不等于2或4.难道不是假的吗?

This is how I read the above. If 1 is equal to 2 or 4, then print true. Otherwise, print false. When this is executed though... true is printed. Obviously I'm misunderstanding something here. 1 is not equal to 2 or 4. Wouldn't that make it false?

推荐答案

是的，我犯了同样的错误.

Yeah, I've made the same mistake.

再读一遍句子:

Read the sentence again:

如果1等于2或4，则打印true.

If 1 is equal to 2 or 4, then print true.

"2"和"4"均表示如果1等于[...]".这意味着该句子只是

The "2" and "4" both refer to the "If 1 is equal to [...]." That means, the sentence is just an abbreviation of

如果1等于2或 1等于 4，则打印true.

If 1 is equal to 2 or 1 is equal to 4, then print true.

这导致我们进入if-条款

if (1 == 2 || 1 == 4)

相反.

1 == 2 || 4为true，因为(1 == 2) == false与4 == true进行或运算，得出true(false或true = true).

1 == 2 || 4 is true because (1 == 2) == false ORed with 4 == true, yields true (false OR true = true).

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