从Android Webview托管的网站中获取用户登录的详细信息 [英] Fetch user signed in details from a website hosted in an android Webview
问题描述
我为我的网站创建了一个Webview android应用程序，以便拥有我的网站的android版本.该网站允许用户登录，然后再访问网站信息.
I created a Webview android app for my website so as to have an android version of my website. The website allows a user to sign in before proceeding to the website information.
请问，如何在Webview android应用中从网站获取用户登录的详细信息(例如电子邮件)?
Please, How do I fetch the user signed in details (e.g email) from the website in my Webview android app?
推荐答案
您可以使用以下函数获取WebView的内容:
You can get the content of the WebView using this function:
yourWebView.evaluateJavascript(
"(function() { return ('<html>'+document.getElementsByTagName('html')[0].innerHTML+'</html>'); })();",
new ValueCallback<String>() {
@Override
public void onReceiveValue(String html) {
Log.d("HTML", html);
// Here you work with the content of the page which is stored in the 'html' variable
}
});
由于您能够阅读页面的内容，因此可以在网站的隐藏字段(例如<input type="hidden" id="emailAddress" name="emailAddress" value="someone@example.org">)中隐藏要阅读的数据.
Since you are able to read the content of the page, you can either hide the data you want to read in the website in a hidden field (e.g. <input type="hidden" id="emailAddress" name="emailAddress" value="someone@example.org">).
或者您可以创建自己的Activity，用户可以在其中插入他的电子邮件地址，然后可以使用WebView.postUrl(String url, byte[] postData)功能(例如webView.postUrl("https://yourWebsite.com/index.php", "emailAddress=someone@example.org".getBytes());)将插入的电子邮件地址发布到您的网站上.
Or you can create a own Activity where the use can insert his email address, and then you can post the inserted email address on your website using the WebView.postUrl(String url, byte[] postData) function (e.g. webView.postUrl("https://yourWebsite.com/index.php", "emailAddress=someone@example.org".getBytes());).
来源: https://developer.android.com/reference/android/webkit/WebView. html 如何从webview获取html内容? 如何发布WebView android的数据
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