如何在CMS PHP中自动注销不活动的用户 [英] How to automatically logout an inactive user in your CMS PHP

问题描述

我正在尝试从CMS中注销不活动的用户.超时值存储在数据库中名为PREF_TIMEOUT的值中.香港专业教育学院借用此代码，并对其进行了一些修改.该代码似乎没有做任何事情.有谁知道这样做的更好方法，还是可以发现破坏它的原因?

I am trying to force log out an inactive user from my CMS. The timeout value is stored in a value called PREF_TIMEOUT in my database. Ive borrowed this code and modified it a little. The code does not seem to be doing anything. Does anyone know of a better method of doing this or can spot what is breaking it?

<?php
function init() {
    parent:: init();
    self::logoutInactiveUser();
}

$timeout = mysql_query("SELECT PREF_TIMEOUT FROM preferences WHERE PREF_ID = '1'");
$result = mysql_fetch_array($timeout);

function logoutInactiveUser() {
    $inactivityLimit = $timeout * 60; // Converted to seconds
    $sessionStart = Session::get('session_start_time');
    if (isset($sessionStart)){
        $elapsed_time = time() - Session::get('session_start_time');
        if ($elapsed_time >= $inactivityLimit) {
            $member = Member::currentUser();
            if($member) $member->logOut();
            Session::clear_all();
            Director::redirect(Director::baseURL() . 'Security/login');
        }
    }
    Session::set('session_start_time', time());
}
?>

推荐答案

在以下链接中参考我的答案:

Refer to my answer at the link: Logout an inactive user using PHP .

根据您当前的代码，问题在于您的查询 $timeout = mysql_query("SELECT PREF_TIMEOUT FROM preferences WHERE PREF_ID = '1'"); $result = mysql_fetch_array($timeout); 在函数 logoutInactiveUser()之外，因此变量 $ timeout 不会包含数据库中的任何数据.在函数内部移动代码应该会对您有所帮助.

As per your current code, the issue is your Queries $timeout = mysql_query("SELECT PREF_TIMEOUT FROM preferences WHERE PREF_ID = '1'"); $result = mysql_fetch_array($timeout); are outside the function logoutInactiveUser(), due to which the variable $timeout will not have any data from your database. Moving the code inside the function should help you.

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