该项目被点击的点击列表视图 [英] which item was clicked in a clickable list view

问题描述

我有一个充满字符串的ArrayList一个ListView
我想使它点击..但我不能承认被点击了哪个项目

我做了这一点，但它不工作！

有没有办法知道点击的字符串？
如果不
是有办法知道点击项目的位置？

 公共类的SearchResult延伸活动{    公众的ArrayList＆LT;串GT; findMovieByName（字符串名称）{
        ArrayList的＆LT;电影和GT;比赛=新的ArrayList＆LT;电影和GT;（）;
        //通过成员名单，并与给定的名称比较名称
        对于（动画电影：MovieReg_activity.movi​​es）{
            如果（movie.getName（）。包含（名称））{
                matches.add（电影）; //添加匹配部件在返回表            }
        }
        ArrayList的＆LT;串GT; matchesNames =新的ArrayList＆LT;串GT;（）;
            INT X = 0;
           对于（动画电影：匹配）{
          串name65 = movie.getName（）;
            matchesNames.add（X，name65）;
            X ++;
                }         返回matchesNames; //返回比赛中，当与给定名称的成员，发现里面是空的
    }
            @覆盖
    保护无效的onCreate（捆绑savedInstanceState）{
        // TODO自动生成方法存根
        super.onCreate（savedInstanceState）;
        的setContentView（R.layout.test）;
        LV的ListView =（ListView控件）findViewById（R.id.listView1）;
        TextView的电视=（的TextView）findViewById（R.id.textView1）;
        束束= getIntent（）getExtras（）。
        如果（捆绑！= NULL）{
        字符串搜索栏= bundle.getString（搜索值）;
         ArrayList的＆LT;串GT;清单= findMovieByName（搜索栏）;
           INT match_size =则为list.size（）;
           tv.setText（不匹配=的+ match_size）;        ArrayAdapter＆LT;串GT;广告=新ArrayAdapter＆LT;串GT;（SearchResults.this，android.R.layout.simple_list_item_1，清单）;
        lv.setAdapter（广告）;        lv.setOnItemClickListener（新OnItemClickListener（）{            @覆盖
            公共无效onItemClick（适配器视图＆LT;＆GT;为arg0，景观位置，INT ARG2，
                    长ARG3）{                    如果（position.equals（1））{
                        Toast.makeText（SearchResults.this，1选择Toast.LENGTH_LONG）.show（）;
                    }其他{
                        Toast.makeText（SearchResults.this，一无所有，Toast.LENGTH_LONG）.show（）;                    }            }
        }）;        }
    }
    }
 

解决方案

 最终的ListView LV =（ListView控件）findViewById（R.id.yourListView）;lv.setOnItemClickListener（新OnItemClickListener（）{
      公共无效onItemClick（适配器视图＆LT;＆GT; myAdapter，查看MyView的，INT myItemInt，长mylng）{
        字符串selectedFromList =（字符串）（lv.getItemAtPosition（myItemInt））;      }
}）;
 

i have a listView which is filled with an arraylist of strings and i want to make it clickable .. but i cant recognize which item was clicked

i've made this but it doesn't work !

is there way to know the string clicked ? if not is there a way to know even the position of clicked item?

public class SearchResults extends Activity{

    public ArrayList<String> findMovieByName(String name) {
        ArrayList<movie> matches = new ArrayList<movie>();
        // go through list of members and compare name with given name
        for(movie movie : MovieReg_activity.movies) {
            if (movie.getName().contains(name)) {
                matches.add(movie); // adds matching member to the return list

            }
        }
        ArrayList<String> matchesNames = new ArrayList<String>();
            int x=0;
           for( movie movie : matches) {
          String name65 =  movie.getName();
            matchesNames.add(x,name65);
            x++ ;
                }

         return matchesNames; // return the matches, which is empty when no member with the given name was found
    }
            @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        setContentView(R.layout.test);
        ListView lv=(ListView)findViewById(R.id.listView1);
        TextView tv=(TextView)findViewById(R.id.textView1);


        Bundle bundle =getIntent().getExtras();
        if(bundle!=null){
        String searchbar =bundle.getString("search value");


         ArrayList<String> list =  findMovieByName(searchbar);
           int match_size=list.size();
           tv.setText("no of matches=" +match_size);



        ArrayAdapter<String> ad = new ArrayAdapter<String>(SearchResults.this, android.R.layout.simple_list_item_1, list);
        lv.setAdapter(ad);

        lv.setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> arg0, View position , int arg2,
                    long arg3) {

                    if( position.equals(1) ){           
                        Toast.makeText(SearchResults.this,"1 chosen", Toast.LENGTH_LONG).show();
                    } else {
                        Toast.makeText(SearchResults.this,"nothing", Toast.LENGTH_LONG).show();

                    }           

            }
        });

        }
    }
    }

解决方案

final ListView lv = (ListView) findViewById(R.id.yourListView);

lv.setOnItemClickListener(new OnItemClickListener() {
      public void onItemClick(AdapterView<?> myAdapter, View myView, int myItemInt, long mylng) {
        String selectedFromList =(String) (lv.getItemAtPosition(myItemInt));

      }                 
});

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