如何在Makefile中编写循环? [英] How to write loop in a Makefile?

问题描述

我要执行以下命令:

./a.out 1
./a.out 2
./a.out 3
./a.out 4
.
.
. and so on

如何在Makefile中将其编写为循环?

How to write this thing as a loop in a Makefile?

推荐答案

如果您假设使用的是./a.out，并且您使用的是UNIX类型的平台，那么下面的步骤将可以解决此问题.

The following will do it if, as I assume by your use of ./a.out, you're on a UNIX-type platform.

for number in 1 2 3 4 ; do \
    ./a.out $$number ; \
done

测试如下:

target:
    for number in 1 2 3 4 ; do \
        echo $$number ; \
    done

产生:

1
2
3
4

对于更大的范围，请使用:

For bigger ranges, use:

target:
    number=1 ; while [[ $$number -le 10 ]] ; do \
        echo $$number ; \
        ((number = number + 1)) ; \
    done

这将输出1到10(含1和10)，只需将while的终止条件从10更改为1000，就可以在注释中指出更大的范围.

This outputs 1 through 10 inclusive, just change the while terminating condition from 10 to 1000 for a much larger range as indicated in your comment.

嵌套循环可以这样完成:

target:
    num1=1 ; while [[ $$num1 -le 4 ]] ; do \
        num2=1 ; while [[ $$num2 -le 3 ]] ; do \
            echo $$num1 $$num2 ; \
            ((num2 = num2 + 1)) ; \
        done ; \
        ((num1 = num1 + 1)) ; \
    done

生产:

1 1
1 2
1 3
2 1
2 2
2 3
3 1
3 2
3 3
4 1
4 2
4 3

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