如何将矩阵的每一行除以固定行? [英] How can I divide each row of a matrix by a fixed row?

问题描述

假设我有一个像这样的矩阵:

Suppose I have a matrix like:

100 200 300 400 500 600
  1   2   3   4   5   6
 10  20  30  40  50  60
...

我希望将每一行除以第二行(每个元素除以相应的元素)，所以我得到:

I wish to divide each row by the second row (each element by the corresponding element), so I'll get:

100 100 100 100 100 100
  1   1   1   1   1   1
 10  10  10  10  10  10
...

我能做到吗(无需编写显式循环)?

Hw can I do it (without writing an explicit loop)?

推荐答案

使用bsxfun:

outMat = bsxfun (@rdivide, inMat, inMat(2,:));

bsxfun的第一个参数是您要应用的函数的句柄，在本例中为右分隔.

The 1st argument to bsxfun is a handle to the function you want to apply, in this case right-division.

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