从数组返回奇数或偶数 [英] Returning an odd or even number from array

问题描述

仅需要帮助您确定我在此Codewar挑战中做错了什么.

Just need help in identifying what I am doing wrong on this codewar challenge.

我意识到这对某些人来说可能很容易，但是请注意，我只是Java语言的初学者.

I realize this may be easy for some but please note I am just a beginner with Javascript.

挑战:

您将获得一个数组(长度至少为3，但是 可能非常大)包含整数.数组要么完全是 由奇数整数组成或完全由偶数整数组成 除了单个整数N.编写一个将数组作为 一个参数并返回N.

You are given an array (which will have a length of at least 3, but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N. Write a method that takes the array as an argument and returns N.

例如:

[2, 4, 0, 100, 4, 11, 2602, 36]应该返回11.

[160, 3, 1719, 19, 11, 13, -21]应该返回160.

我的代码:

function findOutlier(integers){

    var even = [];
    var odd = [];

  for (var i = 0; i < integers; i++) {
    if (integers[i] % 2 === 0) {
        even.push(integers[i]);
    } else {
        odd.push(integers[i]);
    }

    if (even.length === 1) {
        return even;
    } else {
        return odd;
    }
  }
}

推荐答案

另一种可能的方式:

function myFunction(integers) {
  var odds = integers.filter(function(num) {return num % 2});
  var evens = integers.filter(function(num) {return !(num % 2)});
  return evens.length == 1 ? evens[0] : odds[0];
}

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您可以查看此 CodePen演示 在Mocha中测试功能.

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You can check out this CodePen Demo to test the function in Mocha.

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