如何为每个试验有效地去除异常值 [英] How to remove outliers efficiently for each trial

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问题描述

我是R的新手,所以我只知道如何编写循环,但是我绝对认为有一种更有效的方法来执行我要执行的操作.

I'm new to R so all I know is how to write for loops but I definitely think there is a more efficient way to do what I am trying to do.

这是我现在拥有的代码:

Here's the code I have now:

for (i in 1:length(unique(poo$TRIAL_INDEX))) {
zz <- subset(poo, TRIAL_INDEX==i)
sds <- sd(zz$RIGHT_PUPIL_SIZE, na.rm = TRUE)
avgpupil <- mean(zz$RIGHT_PUPIL_SIZE, na.rm = TRUE)
#what im trying to do in the lines above is subset the data for every trial 
#so that I can calculate the standard deviation and average for each trial
for (j in 1:length(zz$RIGHT_PUPIL_SIZE)) {
if (zz$RIGHT_PUPIL_SIZE[j] > 3*sds+avgpupil | zz$RIGHT_PUPIL_SIZE[j] < avgpupil-3*sds | is.na(zz$RIGHT_PUPIL_SIZE[j])) {
  zz$RIGHT_PUPIL_SIZE[j]  <- NA_character_
  goo <- rbind(zz[j],goo)
} else {
  goo <- rbind(zz[j],goo)
}
}
}
#then I want it to replace the value in RIGHT_PUPIL_SIZE with NA if it is 
# 3 SD above or under the mean, and if it's NA. Then I bind it to a new dataframe

我的计算机无法处理此代码. 任何建议都欢迎!

My computer cannot handle this code. Any suggestion is welcomed!

推荐答案

这可能会满足您的大部分需求.我不理解您问题的rbind部分:

This might do most of what you want. I did not understand the rbind part of your question:

poo <- read.table(text = '
     TRIAL_INDEX     RIGHT_PUPIL_SIZE
          1                 10
          1                  8
          1                  6
          1                  4
          1                 NA
          2                  1
          2                  2
          2                 NA
          2                  4
          2                  5
', header = TRUE, stringsAsFactors = FALSE, na.strings = "NA")


my.summary <- as.data.frame(do.call("rbind", tapply(poo$RIGHT_PUPIL_SIZE, poo$TRIAL_INDEX, 
    function(x) c(index.sd = sd(x, na.rm = TRUE), index.mean = mean(x, na.rm = TRUE)))))

my.summary$TRIAL_INDEX <- rownames(my.summary)

poo <- merge(poo, my.summary, by = 'TRIAL_INDEX')

poo$RIGHT_PUPIL_SIZE <- ifelse( (poo$RIGHT_PUPIL_SIZE > (poo$index.mean + 3 * poo$index.sd)) | 
                                (poo$RIGHT_PUPIL_SIZE < (poo$index.mean - 3 * poo$index.sd)) | 
                                is.na(poo$RIGHT_PUPIL_SIZE),  NA, poo$RIGHT_PUPIL_SIZE)

poo

#   TRIAL_INDEX RIGHT_PUPIL_SIZE index.sd index.mean
#1            1               10 2.581989          7
#2            1                8 2.581989          7
#3            1                6 2.581989          7
#4            1                4 2.581989          7
#5            1               NA 2.581989          7
#6            2                1 1.825742          3
#7            2                2 1.825742          3
#8            2               NA 1.825742          3
#9            2                4 1.825742          3
#10           2                5 1.825742          3

这是使用aggregate的解决方案:

my.summary <- with(poo, aggregate(RIGHT_PUPIL_SIZE, by = list(TRIAL_INDEX), 
                   FUN = function(x) { c(index.sd = sd(x, na.rm = TRUE), 
                                         index.mean = mean(x, na.rm = TRUE)) } ))

my.summary <- do.call(data.frame, my.summary)

colnames(my.summary) <- c('TRIAL_INDEX', 'index.sd', 'index.mean')

poo <- merge(poo, my.summary, by = 'TRIAL_INDEX')

poo$RIGHT_PUPIL_SIZE <- ifelse((poo$RIGHT_PUPIL_SIZE > (poo$index.mean + 3 * poo$index.sd)) | 
                               (poo$RIGHT_PUPIL_SIZE < (poo$index.mean - 3 * poo$index.sd)) | 
                               is.na(poo$RIGHT_PUPIL_SIZE),  NA, poo$RIGHT_PUPIL_SIZE)

这是使用ave的解决方案:

index.mean <- ave(poo$RIGHT_PUPIL_SIZE, poo$TRIAL_INDEX, FUN = function(x) mean(x, na.rm = TRUE))
index.sd   <- ave(poo$RIGHT_PUPIL_SIZE, poo$TRIAL_INDEX, FUN = function(x)   sd(x, na.rm = TRUE))

poo <- data.frame(poo, index.mean, index.sd)

poo$RIGHT_PUPIL_SIZE <- ifelse((poo$RIGHT_PUPIL_SIZE > (poo$index.mean + 3 * poo$index.sd)) | 
                               (poo$RIGHT_PUPIL_SIZE < (poo$index.mean - 3 * poo$index.sd)) | 
                               is.na(poo$RIGHT_PUPIL_SIZE),  NA, poo$RIGHT_PUPIL_SIZE)

这是使用dplyr的解决方案,与Dave2e的dplyr解决方案略有不同.他可能更好,因为在发布此答案之前我从未使用过dplyr.

Here is a solution using dplyr that differs a little from the dplyr solution by Dave2e. His is probably better, as I have never used dplyr until posting this answer.

library(dplyr)
my.summary <- poo %>%
    group_by(TRIAL_INDEX) %>% 
    summarise(index.mean = mean(RIGHT_PUPIL_SIZE, na.rm = TRUE), 
                index.sd =   sd(RIGHT_PUPIL_SIZE, na.rm = TRUE))

my.summary

poo <- merge(poo, as.data.frame(my.summary), by = 'TRIAL_INDEX')


poo$RIGHT_PUPIL_SIZE <- ifelse((poo$RIGHT_PUPIL_SIZE > (poo$index.mean + 3 * poo$index.sd)) | 
                               (poo$RIGHT_PUPIL_SIZE < (poo$index.mean - 3 * poo$index.sd)) | 
                               is.na(poo$RIGHT_PUPIL_SIZE),  NA, poo$RIGHT_PUPIL_SIZE)

poo

这是使用data.table的解决方案.使用data.table可能有更好的解决方案.我想我在发布此答案之前只使用过一次data.table.

Here is a solution using data.table. There are probably better solutions using data.table. I think I only used data.table once before posting this answer.

poo <- read.table(text = '
     TRIAL_INDEX     RIGHT_PUPIL_SIZE
          1                 10
          1                  8
          1                  6
          1                  4
          1                 NA
          2                  1
          2                  2
          2                 NA
          2                  4
          2                  5
', header = TRUE, stringsAsFactors = FALSE, na.strings = "NA")

library(data.table)

my.summary <- data.frame(setDT(poo)[, .(index.mean = mean(RIGHT_PUPIL_SIZE, na.rm = TRUE), 
                                          index.sd =   sd(RIGHT_PUPIL_SIZE, na.rm = TRUE)),
                     .(TRIAL_INDEX)])

poo <- merge(poo, my.summary, by = 'TRIAL_INDEX')

poo$RIGHT_PUPIL_SIZE <- ifelse((poo$RIGHT_PUPIL_SIZE > (poo$index.mean + 3 * poo$index.sd)) | 
                               (poo$RIGHT_PUPIL_SIZE < (poo$index.mean - 3 * poo$index.sd)) | 
                               is.na(poo$RIGHT_PUPIL_SIZE),  NA, poo$RIGHT_PUPIL_SIZE)

poo

这篇关于如何为每个试验有效地去除异常值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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